Java | Leetcode Java题解之第523题连续的子数组和
题目：
题解：
class Solution {
public boolean checkSubarraySum(int[] nums, int k) {
int m = nums.length;
if (m < 2) {
return false;
}
Map<Integer, Integer> map = new HashMap<Integer, Integer>();
map.put(0, -1);
int remainder = 0;
for (int i = 0; i < m; i++) {
remainder = (remainder + nums[i]) % k;
if (map.containsKey(remainder)) {
int prevIndex = map.get(remainder);
if (i - prevIndex >= 2) {
return true;
}
} else {
map.put(remainder, i);
}
}
return false;
}
}