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RabbitMQ在手动消费的模式下设置失败重新投递策略

article 2024/12/2 16:13:28

最近在写RabbitMQ的消费者，因为业务需求，希望失败后重试一定次数，超过之后就不处理了，或者放入死信队列。我这里就达到重试次数后就不处理了。本来以为很简单的，问了kimi，按它的方法配置之后，发现报错之后一直重复消费，进入了死循环。

下面是kimi给的“最佳实践”的示例代码：

import org.springframework.amqp.rabbit.annotation.RabbitListener;
import org.springframework.amqp.rabbit.connection.ConnectionFactory;
import org.springframework.amqp.rabbit.listener.RabbitListenerEndpointRegistrar;
import org.springframework.amqp.rabbit.listener.SimpleRabbitListenerContainerFactory;
import org.springframework.amqp.rabbit.listener.api.ChannelAwareMessageListener;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;

@Configuration
public class RabbitMQConfig {

    @Bean
    public SimpleRabbitListenerContainerFactory myFactory(ConnectionFactory connectionFactory) {
        SimpleRabbitListenerContainerFactory factory = new SimpleRabbitListenerContainerFactory();
        factory.setConnectionFactory(connectionFactory);
        factory.setAcknowledgeMode(AcknowledgeMode.MANUAL);
        return factory;
    }
}

import org.springframework.amqp.core.Message;
import org.springframework.amqp.rabbit.annotation.RabbitListener;
import org.springframework.stereotype.Component;

@Component
public class RabbitMQConsumer {

    @RabbitListener(queues = "your-queue-name", containerFactory = "myFactory")
    public void receiveMessage(final Message message, com.rabbitmq.client.Channel channel) {
        // 消息处理逻辑
        try {
            String payload = new String(message.getBody());
            System.out.println("Received message: " + payload);
            // 业务逻辑处理
            // ...

            // 手动确认消息
            channel.basicAck(message.getMessageProperties().getDeliveryTag(), false);
        } catch (Exception e) {
            System.out.println("Error processing message: " + e.getMessage());
            try {
                // 拒绝消息并重新入队
                channel.basicNack(message.getMessageProperties().getDeliveryTag(), false, true);
            } catch (Exception ex) {
                // 如果消息拒绝失败，则关闭通道
                channel.close();
            }
        }
    }
}

问题出在哪里呢？

看起来是很完美的，但是......，还是有漏洞：