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判断按键盘是否好使的开机自启动PowerShell脚本

article 2025/3/4 8:19:01

一、ps1脚本

文件名：KeyboardCheck.ps1

Function WaitForKeyPress($TimeoutInSeconds) {
    $KeyPressed = $false
    $deadline = (Get-Date).AddSeconds($TimeoutInSeconds)
    
    # 显示提示信息
    Write-Host "请在 $TimeoutInSeconds 秒内按下任意键(长时间没有检测到按下按键会被认为键盘可能有问题)" -ForegroundColor Blue

    # 使用 ReadKey 和 Sleep 来实现等待
    while ((Get-Date) -lt $deadline -and !$KeyPressed) {
        if ([Console]::KeyAvailable) {
            # 按键被按下了
            $key = [Console]::ReadKey($true)  # $true 表示不显示按键
            Write-Host "检测到按键 '$($key.KeyChar)' ($($key.Key))" -ForegroundColor Green
            $KeyPressed = $true
        } else {
            Start-Sleep -Milliseconds 100  # 延迟 100 毫秒
        }
    }

    if ($KeyPressed) {
        Write-Host "在 $TimeoutInSeconds 秒内按下了按键。"
    } else {
        Write-Host "$TimeoutInSeconds 秒内没有按键！你的键盘可能有问题！" -ForegroundColor Red
    }

    # 返回是否检测到按键的值
    return $KeyPressed
}

Function ExitWithCountdown {
    param (
        [int]$Seconds = 10  # 默认倒计时时间为10秒
    )

    Write-Host
    Write-Host "脚本将在 $Seconds 秒后自动关闭窗口" -ForegroundColor Magenta
    for ($i = $Seconds; $i -gt 0; $i--) {
        Write-Host -NoNewline "`r正在退出... {$i}秒后关闭窗口..."
        Start-Sleep -Seconds 1
    }
}

# 获取5秒内是否按下了任意键
$IsKeyPressed = WaitForKeyPress -TimeoutInSeconds 5

# 根据 $IsKeyPressed 的值调用 cmd.exe
if ($IsKeyPressed) {
    Start-Process -FilePath "cmd.exe" -ArgumentList "/c echo cmd_t" -NoNewWindow -Wait
} else {
    Start-Process -FilePath "cmd.exe" -ArgumentList "/c echo cmd_f" -NoNewWindow -Wait
}

# 延迟退出
ExitWithCountdown

二、开机自启动

打开路径：%APPDATA%\Microsoft\Windows\Start Menu\Programs\Startup
将下面的代码保存到名为start_KeyboardCheck.bat的文件中
(代码中的文件路径自行修改)

@echo off

echo.
echo ScriptPath:%~dp0

set "ps1Path=C:\MyScript\KeyboardCheck.ps1"

if exist "%ps1Path%" (
    echo File "%ps1Path%" exists
    PowerShell -NoLogo -ExecutionPolicy Bypass -File "%ps1Path%"
) else (
    echo File "%ps1Path%" does not exist, please check the path!
    pause
)