SQL,生成指定时间间隔内的事件次序号
MSSQL 数据库某表有三个字段：账号、字符串类型的日期和时间。
| Account_Number | FuelPurchase_Date | Fuel_TOD |
| 19 | 2024-04-03 | 07:02:02 AM |
| 19 | 2024-04-03 | 07:02:41 AM |
| 19 | 2024-04-03 | 02:58:49 PM |
| 19 | 2024-04-03 | 07:58:49 PM |
| 19 | 2024-04-05 | 02:58:49 PM |
| 19 | 2024-04-05 | 02:59:31 PM |
| 19 | 2024-04-17 | 11:56:13 PM |
| 20 | 2024-04-17 | 11:59:13 PM |
| 19 | 2024-04-18 | 12:15:13 AM |
| 19 | 2024-04-18 | 02:56:13 PM |
| 20 | 2024-04-18 | 07:41:55 AM |
| 20 | 2024-04-18 | 07:41:55 PM |
| 20 | 2024-04-18 | 07:56:55 PM |
| 19 | 2024-04-19 | 07:41:55 AM |
| 19 | 2024-04-19 | 07:42:20 AM |
| 19 | 2024-04-19 | 08:41:20 AM |
现在要新增一个分组的序号列 Seq，当某个账号在一个小时内发生新事件时，Seq+1；如果一个小时后才发生新事件，则重置 Seq 为 1。
| Account_Number | FuelPurchase_Date | Fuel_TOD | Seq |
| 19 | 2024-04-03 | 07:02:02 AM | 1 |
| 19 | 2024-04-03 | 07:02:41 AM | 2 |
| 19 | 2024-04-03 | 02:58:49 PM | 1 |
| 19 | 2024-04-03 | 07:58:49 PM | 1 |
| 19 | 2024-04-05 | 02:58:49 PM | 1 |
| 19 | 2024-04-05 | 02:59:31 PM | 2 |
| 19 | 2024-04-17 | 11:56:13 PM | 1 |
| 19 | 2024-04-18 | 12:15:13 AM | 2 |
| 19 | 2024-04-18 | 02:56:13 PM | 1 |
| 19 | 2024-04-19 | 07:41:55 AM | 1 |
| 19 | 2024-04-19 | 07:42:20 AM | 2 |
| 19 | 2024-04-19 | 08:41:20 AM | 3 |
| 20 | 2024-04-17 | 11:59:13 PM | 1 |
| 20 | 2024-04-18 | 07:41:55 AM | 1 |
| 20 | 2024-04-18 | 07:41:55 PM | 1 |
| 20 | 2024-04-18 | 07:56:55 PM | 2 |
编写SPL代码
| A | |
| 1 | =mssql.query("select *,cast(FuelPurchase_Date as datetime) + cast(Fuel_TOD as datetime) as DT from tb order by Account_Number,DT”) |
| 2 | =A1.new(Account_Number,FuelPurchase_Date,Fuel_TOD, if(Account_Number==Account_Number[-1] && interval@s(Fuel_DT[-1],Fuel_DT)<3600,Seq[-1]+1,1):Seq) |
A1：通过JDBC查询数据库，拼出日期时间类型的计算列DT，并按账号和DT排序。
A2：新建二维表，增加新计算列Seq。当前记录的账号与上一条记录相同，且时间间隔一小时内时，Seq+1；否则将Seq重置为1。[-1]表示相对位置的上一条记录。
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