集合帖:区间问题
一、AcWing 803:区间合并
(1)题目来源:https://www.acwing.com/problem/content/805/
(2)算法代码:https://blog.csdn.net/hnjzsyjyj/article/details/145067059
#include <bits/stdc++.h>
using namespace std;
const int maxn=1e5+5;
struct Section {
int x;
int y;
} a[maxn];
bool cmp(Section u,Section v) {
if(u.x==v.x) return u.y<v.y;
return u.x<v.x;
}
int main() {
int n;
cin>>n;
for(int i=1; i<=n; i++) {
cin>>a[i].x>>a[i].y;
}
sort(a+1,a+1+n,cmp);
int base=a[1].y;
int cnt=1;
for(int i=1; i<=n; i++) {
if(a[i].x<=base) base=max(base,a[i].y);
else cnt++,base=a[i].y;
}
cout<<cnt<<endl;
return 0;
}
/*
in:
10
-15 -8
-20 23
-2 11
2 22
18 23
11 27
-8 21
-18 14
-17 -12
-23 8
out:
1
*/
二、洛谷 P1496:火烧赤壁
(1)题目来源:https://www.luogu.com.cn/problem/P1496
(2)算法代码:https://blog.csdn.net/hnjzsyjyj/article/details/145073398
#include <bits/stdc++.h>
using namespace std;
const int maxn=2e5;
struct Point {
int x;
int y;
} a[maxn];
bool cmp(Point u,Point v) {
if(u.x==v.x) return u.y<v.y;
return u.x<v.x;
}
int main() {
int n;
cin>>n;
for(int i=1; i<=n; i++) {
cin>>a[i].x>>a[i].y;
}
sort(a+1,a+1+n,cmp);
int cnt=0;
int from=a[1].x;
int base=a[1].y;
for(int i=1; i<=n; i++) {
if(a[i].x<=base) base=max(base,a[i].y);
else {
cnt+=(base-from);
from=a[i].x;
base=a[i].y;
}
}
cnt+=(base-from);
cout<<cnt<<endl;
return 0;
}
/*
in:
3
-1 1
5 11
2 9
out:
11
*/
三、AcWing 905:区间选点
(1)题目来源:https://www.acwing.com/problem/content/907/
(2)算法代码:https://blog.csdn.net/hnjzsyjyj/article/details/142840548
#include <bits/stdc++.h>
using namespace std;
const int inf=0x3f3f3f3f;
const int maxn=1e5+5;
struct Scope {
int le,ri;
} a[maxn];
bool up(Scope u,Scope v) {
return u.ri<v.ri;
}
int main() {
int n;
cin>>n;
for(int i=0; i<n; i++) {
cin>>a[i].le>>a[i].ri;
}
sort(a,a+n,up);
int ans=0;
int t_ri=-inf;
for(int i=0; i<n; i++)
if(t_ri<a[i].le) {
ans++;
t_ri=a[i].ri;
}
cout<<ans<<endl;
return 0;
}
/*
in:
3
-1 1
2 4
3 5
out:
2
*/
四、AcWing 906:区间分组
(1)题目来源:https://www.acwing.com/problem/content/908/
(2)算法代码:https://blog.csdn.net/hnjzsyjyj/article/details/145081557
#include <bits/stdc++.h>
using namespace std;
const int maxn=1e5+5;
pair<int,int> a[maxn];
int n;
int main() {
cin>>n;
for(int i=0; i<n; i++) {
cin>>a[i].first>>a[i].second;
}
sort(a,a+n);
priority_queue<int,vector<int>,greater<int>> q;
for(int i=0; i<n; i++) {
if(q.size() && a[i].first>q.top()) q.pop();
q.push(a[i].second);
}
cout<<q.size()<<endl;
return 0;
}
/*
in:
10
-15 -8
-20 23
-2 11
2 22
18 23
11 27
-8 21
-18 14
-17 -12
-23 8
out:
6
*/
五、AcWing 907:区间覆盖
(1)题目来源:https://www.acwing.com/problem/content/909/
(2)算法代码:https://blog.csdn.net/hnjzsyjyj/article/details/145083747
#include <bits/stdc++.h>
using namespace std;
const int maxn=1e5+5;
struct Section {
int x;
int y;
} a[maxn];
bool cmp(Section u,Section v) {
if(u.x==v.x) return u.y<v.y;
return u.x<v.x;
}
int main() {
int st,en;
cin>>st>>en;
int n;
cin>>n;
for(int i=1; i<=n; i++) {
cin>>a[i].x>>a[i].y;
}
sort(a+1,a+1+n,cmp);
int ans=0;
bool flag=false;
for(int i=1; i<=n; i++) {
int j=i,t=INT_MIN;
while(j<=n && a[j].x<=st) {
t=max(t,a[j].y);
j++;
}
if(t<st) break;
ans++;
if(t>=en) {
flag=true;
break;
}
st=t,i=j-1;
}
if(!flag) ans=-1;
cout<<ans<<endl;
return 0;
}
/*
in:
1 5
3
-1 3
2 4
3 5
out:
2
*/
六、AcWing 802:区间和
(1)题目来源:https://www.acwing.com/problem/content/804/
(2)算法代码:https://blog.csdn.net/hnjzsyjyj/article/details/143309807
#include <bits/stdc++.h>
using namespace std;
typedef pair<int,int> PII;
const int maxn=3e5+5;
int a[maxn],s[maxn];
int n,m;
vector<int> alls;
vector<PII> add,query;
int find(int x) { //discretization
int le=0;
int ri=alls.size()-1;
while(le<ri) {
int mid=(le+ri)>>1;
if(alls[mid]>=x) ri=mid;
else le=mid+1;
}
return ri+1;
}
int main() {
cin>>n>>m;
for(int i=0; i<n; i++) {
int x,c;
cin>>x>>c;
alls.push_back(x);
add.push_back({x,c});
}
for(int i=0; i<m; i++) {
int le,ri;
cin>>le>>ri;
alls.push_back(le), alls.push_back(ri);
query.push_back({le,ri});
}
//de-weight
sort(alls.begin(),alls.end());
alls.erase(unique(alls.begin(),alls.end()), alls.end());
for(auto v:add) {
int x=find(v.first);
a[x]+=v.second;
}
for(int i=1; i<=alls.size(); i++) {
s[i]=s[i-1]+a[i]; //prefix sum
}
for(auto v:query) {
int le=find(v.first);
int ri=find(v.second);
cout<<s[ri]-s[le-1]<<endl;
}
return 0;
}
/*
in:
3 3
1 2
3 6
7 5
1 3
4 6
7 8
out:
8
0
5
*/