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力扣刷题125. 验证回文串

article 2025/3/10 9:05:56

125. 验证回文串 - 力扣（LeetCode）

直接遍历字符串即可，用stringbuilder 中的service反转字符串，然后再用equalsIgnoreCase进行判断

class Solution {
    public boolean isPalindrome(String s) {
                StringBuilder sb = new StringBuilder();
        for (int i = 0; i < s.length(); i++) {
            char c = s.charAt(i);
            int num =  c;
            //System.out.println(num);
            if ((num >= 65 && num <= 90) || (num >= 97 && num <= 122)|| (num >= 48 && num <= 57)){
                //System.out.println(c);
                sb.append(c);
            }
        }
        String s1 = sb.toString();
        String s2 = sb.reverse().toString();
//        System.out.println(s1);
//       System.out.println(s2);
        if(s1.equalsIgnoreCase(s2))return true;
        else return false;
    }
}

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