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（八）使用Postman工具调用WebAPI

article 2024/11/14 10:20:30

访问WebAPI的方法，Postman工具比SoapUI好用一些。

1.不带参数的get请求

[HttpGet(Name = "GetWeatherForecast")]
public IEnumerable<WeatherForecast> Get()
{
    return Enumerable.Range(1, 5).Select(index => new WeatherForecast
    {
        Date = DateTime.Now.AddDays(index),
        TemperatureC = Random.Shared.Next(-20, 55),
        Summary = Summaries[Random.Shared.Next(Summaries.Length)]
    })
    .ToArray();
}

2.带参数的get请求

[HttpGet]
public WeatherForecast GetWeatherForecastById(int id)
{
    return new WeatherForecast
    {
        Date = DateTime.Now.AddDays(id),
        TemperatureC = Random.Shared.Next(-20, 55),
        Summary = Summaries[Random.Shared.Next(Summaries.Length)]
    };
}

3.post请求

[HttpPost]
public string PostWeatherForecast([FromBody] WeatherForecast message, [FromQuery] string param)
{
    //定义json格式返回结果
    var result = new { code = 0, city = param, data = message };
    return JsonConvert.SerializeObject(result);
    //return JsonSerializer.Serialize(result);
}

可以通过Body->form-data来传递两个参数：