Python根据图片生成学生excel成绩表
学习笔记:
上完整代码
import os import re from openpyxl import Workbook, load_workbook from openpyxl.drawing.image import Image as ExcelImage from PIL import Image as PilImage # 定义图片路径和Excel文件路径 image_dir = './resources/stupics' # 图片所在的文件夹路径,请根据实际情况修改 excel_path = './result/students_info.xlsx' # Excel文件路径,请根据实际情况修改 output_folder = './result'; if not os.path.exists(output_folder): os.makedirs(output_folder) # 定义图片名称格式的正则表达式 pattern = r'(?P<grade>\d{2})级(?P<major>[\u4e00-\u9fff]+)(?P<class>\d+班)(?P<name>[\u4e00-\u9fff]+)' # 获取图片文件列表 image_files = [f for f in os.listdir(image_dir) if f.endswith(('.png', '.jpg', '.jpeg'))] # 检查是否存在Excel文件,若不存在则创建新文件 if not os.path.exists(excel_path): wb = Workbook() ws = wb.active ws.title = "学生信息" # 写入表头 headers = ["年级", "专业", "班级", "姓名", "照片"] ws.append(headers) else: wb = load_workbook(excel_path) ws = wb.active # 定义各列的固定宽度 column_widths = { 'A': 10, # 年级 'B': 25, # 专业 'C': 8, # 班级 'D': 15, # 姓名 'E': 15 # 照片 } # 应用固定列宽 for column, width in column_widths.items(): ws.column_dimensions[column].width = width # 遍历图片文件,解析名称并写入Excel for image_file in image_files: match = re.match(pattern, os.path.splitext(image_file)[0]) if match: info = match.groupdict() row = [ info['grade'] + '级', info['major'], info['class'], info['name'] ] ws.append(row) # 确保图片插入到正确的行 img_path = os.path.join(image_dir, image_file) img = PilImage.open(img_path) excel_img = ExcelImage(img_path) excel_img.width, excel_img.height = 80, 110 # 根据需要调整图片大小 # 计算图片宽度对应的字符数 pixel_width = excel_img.width char_width = pixel_width / 7 # 假设每个字符约等于7个像素 # 设置图片所在列的宽度 cell_location = f'E{ws.max_row}' # 使用当前最大行数作为图片插入位置 ws.add_image(excel_img, cell_location) ws.column_dimensions['E'].width = char_width # 计算行高(假设每点约等于1.33像素) pixel_height = excel_img.height point_height = pixel_height / 1.33 # 设置行高 ws.row_dimensions[ws.max_row].height = point_height # 保存工作簿 wb.save(excel_path) print("数据已成功写入Excel文件")
这是结构
运行结果及其展示
免费,需要q